NSURL object not an Objective-C object

Question

I am trying to make a URL with a string using the following code

NSString *urlStr = [NSString stringWithFormat:@"http://demo.com"];
NSURL *url = [NSURL urlWithString:urlStr];

But the URL is always coming up nil. When I print description of the URL, I get:

Printing description of url:(NSURL *) url = 0xbfffdb78 (not an Objective-C object)

Can anyone help me and what am I missing?

Is that the actual URL in your code? No variable parameters (you use stringWithFormat after all)? — Thilo, Oct 19 '12 at 09:20
Also, it should be `[NSURL URLWithString: urlStr];` (notice capital letters). — , Oct 19 '12 at 09:22
Printing description of url: (NSURL *) url = 0xbfffdb78 this is what i am getting, even if i do NSURL *url = [NSURL alloc]init]; — Vishal Singh, Oct 19 '12 at 09:37

score 2 · Answer 1 · edited Oct 19 '12 at 11:16

2

Try this,

      NSString *urlstr=[NSString stringWithFormat:@"http://google.com"];

      urlstr = [urlstr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

      NSURL * url=[NSURL URLWithString:urlstr];

edited Oct 19 '12 at 11:16

Popeye

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answered Oct 19 '12 at 09:58

btmanikandan

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AppleDelegate · Answer 2 · 2012-10-19T09:34:53.853

0

The description of NSURL or NSMutableURL shall be printed in this way

  NSLog(@"%@",url.absoluteString);

edited Oct 19 '12 at 09:34

answered Oct 19 '12 at 09:21

AppleDelegate

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Can you explain how this answers the question? – jamesmortensen Oct 19 '12 at 09:27
1

As a sidenote, you shouldn't use `NSLog` like this, you should always use a format string, i.e. `NSLog(@"%@", url.description)`. – Pascal Oct 19 '12 at 09:34

NSURL object not an Objective-C object

2 Answers2