How to replace with starting and ending with asterik

Question

How do I get the required output?

input string :

 " software Company(1920 of 2012)(sb.2)(sb.3) IBM on established (2009)"

word to be searched -

"software company(1920 of 2012)"

Output

*software Company(1920 of 2012)*(sb.2)(sb.3) IBM on established (2009)

In short I have to find a phrase and replace the same phrase with starting and ending with asterisk (*), IGNORING THE CASE, and MATCH EXACT WORLD i

Stop SHOUTING at us. [What have you tried?](http://www.whathaveyoutried.com/) — Andrew Thompson, Oct 18 '12 at 06:51
I'm not sure what you want to do. Are you trying to see if a given string contains the second string? — Keppil, Oct 18 '12 at 06:52
You could have easily googled it. Think a bit before you ask a question. — akaHuman, Oct 18 '12 at 06:57

score 0 · Accepted Answer · answered Oct 18 '12 at 06:57

You can do this easily using String#replaceAll() :

String original =  " software Company(1920 of 2012)(sb.2)(sb.3) IBM on established (2009)";
String subString = "software company(1920 of 2012)";
System.out.println("New String is: " + original.replaceAll("(?i)" + Pattern.quote(subString), "*$0*"));

The (?i) is added to make it case insensitive, and the Pattern#quote() is used to escape special regex characters in your substring.

This prints:

New String is:  *software Company(1920 of 2012)*(sb.2)(sb.3) IBM on established (2009)

How to replace with starting and ending with asterik

1 Answers1