Checking value of argc

Question

I have problem with the number of argc that passed to program
so, when i check the argc it's not equal to 2 !!
need help, how can i solve that problem ?

C code snippet :

if (2 != argc) {
    fprintf(stderr, "Usage: %s <port>\n", argv[0]);
    exit(1);
}

Yeah, I'm not sure what is being asked here -- the code snipped seems to accomplish exactly what you want. — nickolayratchev, Oct 15 '12 at 21:23
I fixed the title to somewhat relate to your question, but you should really try to improve this more. — Brendan Long, Oct 15 '12 at 21:24
Also, this problem has **nothing to do with sockets.** You could have tagged this question with `perl` or `automatic reference counting` as well... — , Oct 15 '12 at 21:24
The code given seems to be correct, your issue is most likely elsewhere. — OmnipotentEntity, Oct 15 '12 at 21:30
i have to get at least 2 argc to start dealing with port number — MostafaKhattab, Oct 15 '12 at 21:31
The code provided is correct. Your problem is somewhere else. رمز هو الصحيح. مشكلتك هو في مكان آخر. — OmnipotentEntity, Oct 15 '12 at 21:35

score 6 · Answer 1 · answered Oct 15 '12 at 21:23

6

Don't forget that the program name itself counts as an arg.

myProgram -flag variable is an argc of 3

answered Oct 15 '12 at 21:23

octal9

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Checking value of argc

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