Why am I getting a floating point exception error?

Question

I am a novice programmer, so please deal with me. I'm writing a program to analyze data. When I execute the program, I receive a "floating point exception" and I have no clue why. Here is the section of code where the error is originating from. From what I can tell, the if statement seems to be the problem but I do not understand why. Any help you can give is greatly appreciated!

double tArray[600][49];

void main() {
  double finalArray[600][0]
  double n = 0;
  int h = 0;
  try {
    for (int i = 0; i < 600; j++) {
      for (int j = 1; j < 16; j++) {
        h++;
        n = tArray[i][j * 3 - 1] - tArray[i][j * 3 - 2];
        double t = -30;
        if (n < t) {
          finalArray[i][0] = tArray[h][3 * j] - tArray[h + t][3 * j];
          h++;
        }
      }
    }
  }
}

You're incrementing 'h' inside the inner loop, and then using it as the first index in tArray - it will go over 600 pretty darn quickly. — Paul Tomblin, Oct 14 '12 at 01:19
We can assume that missing semicolon in `double finalArray[600][0]` is just a typo, right? — cHao, Oct 14 '12 at 01:23
Is the `j++` in the `for(int i = 0; i < 600; j++)` loop a typo? What is the `try` block for? This isn't your real code is it? It's a mess. — Blastfurnace, Oct 14 '12 at 01:24
Throw away whatever book told you to use `void main()`. It's `int main()`. — Keith Thompson, Oct 14 '12 at 01:50
You're not getting a floating-point exception with the code you posted, because it has numerous syntax errors. Please post your real code. Copy-and-paste it, don't re-type it. @cHao: Type missing semicolon is probably a typo; the `[0]` could also be a typo. — Keith Thompson, Oct 14 '12 at 01:53

score 1 · Accepted Answer · answered Oct 14 '12 at 01:18

Try declaring finalArray as:

double finalArray[600][1];

It appears that the original declaration did not allocate any space for the elements.

If not try allocating only a single dimensional array like this:

double finalArray[600];

Hope this helps!

score 1 · Answer 2 · answered Oct 14 '12 at 01:19

1

Declaring double finalArray[600][0] means the array is 600 elements by 0 elements. I think you want the second dimension to be 1. Remember, you need to declare the number of rows and columns, but indices start at 0.

answered Oct 14 '12 at 01:19

Adam Liss

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Why am I getting a floating point exception error?

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