python 2.7 os.path.dirname(file) returns empty string on Debian (works fine on Win7)

Question

Possible Duplicate:
os.path.dirname(__file__) returns empty

Here's my piece of code:

def GetAppPath():
    application_path = None
    if getattr(sys, 'frozen', False):
        application_path = os.path.dirname(sys.executable)
    elif __file__:
        application_path = os.path.dirname(__file__)
    return application_path

Works perfectly on Windows, but returns empty string on Debian. Any ideas what could be the problem?

I'm using Python 2.7.3, Debian 6.0.5

Have you thought about adding print statements to inspect which branch of the conditional clause you enter? — mgilson, Oct 12 '12 at 14:49
http://stackoverflow.com/questions/7783308/os-path-dirname-file-returns-empty — Artur Gadelshin, Oct 12 '12 at 15:06
@mgilson: I've inspected the branches: the second one is executed — Max Gruzin, Oct 15 '12 at 07:08
@Artur Gadelshin: thank you that's what I was looking for. Too bad I didn't notice it myself — Max Gruzin, Oct 15 '12 at 07:10

score 1 · Answer 1 · edited Oct 12 '12 at 15:22

1

Seems like __file__ is not defined or defined incorrectly, works for me on Debian testing, Python 2.7.3rc2

    def GetAppPath(file):
        application_path = os.path.dirname(file)
        return application_path

GetAppPath('/etc/X11/xorg.conf') returns '/etc/X11'

edited Oct 12 '12 at 15:22

hughdbrown

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answered Oct 12 '12 at 15:09

insider

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score 1 · Answer 2 · answered Oct 12 '12 at 15:21

1

Works for me on Ubuntu 12.04/python 2.7:

import os.path

print os.path.dirname(__file__)

Store in /tmp/foo.py and then run it:

$ python /tmp/foo.py 
/tmp

answered Oct 12 '12 at 15:21

hughdbrown

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python 2.7 os.path.dirname(__file__) returns empty string on Debian (works fine on Win7)

2 Answers2

python 2.7 os.path.dirname(file) returns empty string on Debian (works fine on Win7)