As I understand the following is valid for boost::shared_ptr:
boost::shared_ptr<SomeData> ptr;
...
boost::shared_ptr<const SomeData> c_ptr = ptr; // Valid
The same behavior does not hold for boost::interprocess::managed_shared_ptr
. Why?
As I understand the following is valid for boost::shared_ptr:
boost::shared_ptr<SomeData> ptr;
...
boost::shared_ptr<const SomeData> c_ptr = ptr; // Valid
The same behavior does not hold for boost::interprocess::managed_shared_ptr
. Why?
boost::interprocess::managed_shared_ptr
isn't actually a shared pointer; it's just a helper class that you can use to define the type of one. From the interprocess docs:
typedef managed_shared_ptr<MyType, managed_shared_memory>::type my_shared_ptr;
And the creation of a shared pointer can be simplified to this:
[c++]
my_shared_ptr sh_ptr = make_managed_shared_ptr (segment.construct<MyType>("object to share")(), segment);
With "sh_ptr
" from the above example, the following should work:
typedef managed_shared_ptr<const MyType, managed_shared_memory>::type my_shared_const_ptr;
my_shared_const_ptr sh_c_ptr = sh_ptr;
As these two objects are actually shared pointers.
On the other hand, doing:
managed_shared_ptr<MyType, managed_shared_memory> ptr;
managed_shared_ptr<const MyType, managed_shared_memory> c_ptr = ptr;
won't work because in this case ptr and c_ptr are very simple structs that do nothing except make 3 typedefs, so they don't convert.