I was implementing a recursive function with memoization for speed ups. The point of the program is as follows:
I shuffle a deck of cards (with an equal number of red and black cards) and start dealing them face up. After any card you can say “stop”, at which point I pay you $1 for every red card dealt and you pay me $1 for every black card dealt. What is your optimal strategy, and how much would you pay to play this game?
My recursive function is as follows:
double Game::Value_of_game(double number_of_red_cards, double number_of_black_cards)
{
double value, key;
if(number_of_red_cards == 0)
{
Card_values.insert(Card_values.begin(), pair<double, double> (Key_hash_table(number_of_red_cards, number_of_black_cards), number_of_black_cards));
return number_of_black_cards;
}
else if(number_of_black_cards == 0)
{
Card_values.insert(Card_values.begin(), pair<double, double> (Key_hash_table(number_of_red_cards, number_of_black_cards), 0));
return 0;
}
card_iter = Card_values.find(Key_hash_table(number_of_red_cards, number_of_black_cards));
if(card_iter != Card_values.end())
{
cout << endl << "Debug: [" << number_of_red_cards << ", " << number_of_black_cards << "] and value = " << card_iter->second << endl;
return card_iter->second;
}
else
{
number_of_total_cards = number_of_red_cards + number_of_black_cards;
prob_red_card = number_of_red_cards/number_of_total_cards;
prob_black_card = number_of_black_cards/number_of_total_cards;
value = max(((prob_red_card*Value_of_game(number_of_red_cards - 1, number_of_black_cards)) +
(prob_black_card*Value_of_game(number_of_red_cards, number_of_black_cards - 1))),
(number_of_black_cards - number_of_red_cards));
cout << "Check: value = " << value << endl;
Card_values.insert(Card_values.begin(), pair<double, double> (Key_hash_table(number_of_red_cards, number_of_black_cards), value));
card_iter = Card_values.find(Key_hash_table(number_of_red_cards , number_of_black_cards ));
if(card_iter != Card_values.end());
return card_iter->second;
}
}
double Game::Key_hash_table(double number_of_red_cards, double number_of_black_cards)
{
double key = number_of_red_cards + (number_of_black_cards*91);
return key;
}
The third if statement is the "memoization" part of the code, it stores all the necessary values. The values that are kept in the map can be thought of as a matrix, these values will correspond to a certain #red cards and #black cards. What is really werid is that when I execute the code for 8 cards in total (4 blacks and 4 reds), I get an incorrect answer. But when I execute the code for 10 cards, my answer is wrong, but now my answer for 4 blacks and 4 reds are correct (8 cards)! Same can be said for 12 cards, where I get the wrong answer for 12 cards, but the correct answer for 10 cards, so on and so forth. There is some bug in the code, however, I can't figure it out.