Error 0:0:0:0:0:0:0:1%0 getting IP V6 client

Question

I have this function to get the HostAddress from my request (HttpServletRequest) on Java. But using Jetty 7.x and my IP is ipV6 I have always this error with iPv6 address.

My function:

xxxx.getIP(request, false);

public static String getIP(HttpServletRequest request, boolean proxy) {
    String ip = "";
    log.debug("X-getHeaderNames ["+ request.getHeaderNames()+"]");
    if (proxy) {
        ip = XFordwardedInetAddressUtil.getAddressFromRequest(request);
    } else {
        String _ip = request.getRemoteAddr();
        ip = InetAddresses.forString(_ip).getHostAddress();
    }
    return ip;
}

The error:

DEBUG: org.encuestame.core.exception.EnMeMappingExceptionResolver - Resolving exception from handler [org.encuestame.mvc.controller.TweetPollController@4fc23996]: java.lang.IllegalArgumentException: '0:0:0:0:0:0:0:1%0' is not an IP string literal. java.lang.IllegalArgumentException: '0:0:0:0:0:0:0:1%0' is not an IP string literal. at org.encuestame.utils.net.InetAddresses.forString(InetAddresses.java:59) at org.encuestame.core.util.EnMeUtils.getIP(EnMeUtils.java:210) at org.encuestame.mvc.controller.AbstractBaseOperations.getIpClient(AbstractBaseOperations.java:262) at org.encuestame.mvc.controller.TweetPollController.detailTweetPollController(TweetPollController.java:332) at org.encuestame.mvc.controller.TweetPollController$$FastClassByCGLIB$$6990b004.invoke() at net.sf.cglib.proxy.MethodProxy.invoke(MethodProxy.java:191) at org.springframework.aop.framework.Cglib2AopProxy$DynamicAdvisedIntercepto

I know the iPv6 localhost format should be '0:0:0:0:0:0:0:1' but my request always return this string '0:0:0:0:0:0:0:1%0'

Anyone can help me?

Augusto · Accepted Answer · 2012-10-06T14:59:38.460

3

The problem is that the class you're using (org.encuestame.utils.net.InetAddresses) clearly doesn't support IPv6. Try using the java InetAddress class that Joachim mentioned in his answer.

edited Oct 06 '12 at 14:59

answered Oct 06 '12 at 12:40

Augusto

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score 2 · Answer 2 · edited May 23 '17 at 11:45

2

When you're using a link local address, the % should be included in the address.

This is due to the fact that the computer needs to know which interface/zone the request came from to be able to reply out the correct interface.

If you're using correctly configured, Internet routable IPv6 addresses, the zone index will not be a part of the address.

In this case, I can't see a way to solve your problem for localhost/link local testing except to filter out anything after the % sign, or use another class that works with link local addresses to parse the address.

EDIT: Here's another - similar - question I didn't see earlier.

edited May 23 '17 at 11:45

Community

1
1

answered Oct 06 '12 at 12:33

Joachim Isaksson

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::1 (which is the same as 0:0:0:0:0:0:0:1) is the localhost address. It is not a link-local address (which are from fe80::/10) – Sander Steffann Oct 06 '12 at 13:39
@SanderSteffann You're right of course, trying to locate a reference, but a zone index is optional/allowed even on localhost addresses. Tomcat7 always seems to add it. – Joachim Isaksson Oct 06 '12 at 13:54

Error 0:0:0:0:0:0:0:1%0 getting IP V6 client

2 Answers2