c sscanf with character delimiter

Question

I have an input string of the form

char *s = "one.two three"

and I want to separate it into 3 string variables. I'm doing

sscanf(s, "%s.%s %s", one, two, three);

but it's reading in "one.two" as the string for variable one. How do I handle the "." and the whitespace with sscanf?

cnicutar · Accepted Answer · 2012-09-29T17:10:49.063

4

The %s specifier only stops for a space. Try something like:

sscanf(s, "%[^.].%s %s", one, two, three);

Interestingly, it's likely impossible to produce an acceptable input for "%s.%s %s" since %s only stops for a space yet a . must immediately follow it.

edited Sep 29 '12 at 17:10

answered Sep 29 '12 at 17:01

cnicutar

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Just when you thought you knew everything about scanf format specifiers =P – WhozCraig Sep 29 '12 at 17:20
I would be very sur... I _am_ very surprised that this actually works :-) – John Dvorak Sep 29 '12 at 18:10

c sscanf with character delimiter

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