utext_openUTF8 return error for string "mod-12k";

Question

In following small program I cant figure out why the utext_openUTF8 return with error..

  int utf8_is_it_model3(std::string input_string)
  {
int error_number=0;
UText *ut = NULL;
    UErrorCode status;

    //char *pEnd;
const char * c2 = input_string.c_str();
    ut = utext_openUTF8(ut, c2, -1, &status);
 if(U_FAILURE(status))
 {
            error_number=-1
    std::cout<<" Error!\n";
    return error_number;
 }



utext_close(ut);

 return error_number;

 }   

int main(int argc, char* argv[])
{
int i;
bool is_it_model=false;
std::string input_string="mod-12k";
//std::string input_string="m54-q";
//std::string input_string="- ";
i=utf8_is_it_model3(input_string);

return 0;
    }

output: Error!

when I change the std::string input_string="mod-12k"; with the std::string input_string="sko-w"; I have no error...

I am using ubuntu 64 bit 12.04 and c++ and ICU 49

I cant find out what i am doing wrong...

Print your string content in hex when you output an error. You just might find a surprise. — n. m. could be an AI, Sep 27 '12 at 12:45
std::locale::global(std::locale("")); std::cout.imbue(std::locale()); adding the above line make the bug solved. — user1675224, Sep 27 '12 at 12:57
@user1675224 if that solved it, please add an answer to your own question and mark it solved. — Steven R. Loomis, Oct 16 '12 at 15:37
@user1675224 The line you put in shouldn't be necessary and doesn't really fix it. You're liable to randomly fail unless you initialize the UErrorCode properly. — Steven R. Loomis, Nov 13 '12 at 00:47

score 1 · Answer 1 · answered Oct 16 '12 at 17:33

1

The real problem is you need this on line 5:

UErrorCode status = U_ZERO_ERROR;

answered Oct 16 '12 at 17:33

Steven R. Loomis

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utext_openUTF8 return error for string "mod-12k";

1 Answers1