Get part of array string

Question

Hello my output PHP code is :

Array ( [country] => BG - Bulgaria )

... and he comes from here :

<?php
       $ip = $_SERVER['REMOTE_ADDR'];
       print_r(geoCheckIP($ip));
       //Array ( [domain] => dslb-094-219-040-096.pools.arcor-ip.net [country] => DE - Germany [state] => Hessen [town] => Erzhausen )

       //Get an array with geoip-infodata
       function geoCheckIP($ip)
       {
               //check, if the provided ip is valid
               if(!filter_var($ip, FILTER_VALIDATE_IP))
               {
                       throw new InvalidArgumentException("IP is not valid");
               }

               //contact ip-server
               $response=@file_get_contents('http://www.netip.de/search?query='.$ip);
               if (empty($response))
               {
                       throw new InvalidArgumentException("Error contacting Geo-IP-Server");
               }

               //Array containing all regex-patterns necessary to extract ip-geoinfo from page
               $patterns=array();

               $patterns["country"] = '#Country: (.*?)&nbsp;#i';

               //Array where results will be stored
               $ipInfo=array();

               //check response from ipserver for above patterns
               foreach ($patterns as $key => $pattern)
               {
                       //store the result in array
                       $ipInfo[$key] = preg_match($pattern,$response,$value) && !empty($value[1]) ? $value[1] : '';
               }

               return $ipInfo;
       }

?>

How can I get ONLY the name of the Country like in my case "Bulgaria"? I think it will happen with preg_replace or substr but i dont know what is the better solution now.

score 2 · Answer 1 · answered Sep 26 '12 at 15:29

2

substr's probably easiest:

$bad_country = 'BG - Bulgaria';
$good_country = substr($bad_country, 5); // start at char 5, 'B'

answered Sep 26 '12 at 15:29

Marc B

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score 0 · Answer 2 · answered Sep 26 '12 at 15:30

0

if the country is always separated from the acronym by ' - ', do it like this:

list($acrn, $country) = explode(' - ', $var);

answered Sep 26 '12 at 15:30

dnagirl

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score 0 · Answer 3 · answered Sep 26 '12 at 15:35

If you are guaranteed that the output will always be in the same format(ie BG - Bulgaria, US - United States, etc), you could use explode():

$array['country'] = "BG - Bulgaria";
$country = explode(" - ", $array['country']);
echo $country[1];

This will output "Bulgaria".

Teena Thomas · Answer 4 · 2012-09-26T15:46:46.477

0

try:

    foreach( $list as $v) {
     $temp = explode(' - ', $v);        
     $countries[] = $temp[1];
}

edited Sep 26 '12 at 15:46

answered Sep 26 '12 at 15:36

Teena Thomas

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score 0 · Answer 5 · answered Sep 26 '12 at 15:47

0

$patterns["country"] = '#Country:.*-\s+(\w+?)&nbsp;#i';

try this one as your pattern

answered Sep 26 '12 at 15:47

Surace

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u already have pattern and i guess you dont want to use preg_replace or substr as it will add extra unnecessary computaion – Surace Sep 26 '12 at 15:50

score 0 · Answer 6 · answered Sep 26 '12 at 16:07

0

Change your pattern to this:

'#Country: [a-z]{2,} - (.*?)&nbsp;#i'

Assuming the pattern won't change

answered Sep 26 '12 at 16:07

Ja͢ck

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Get part of array string

6 Answers6