5

I have an enum as a public memebr of a class as follows"

class myClass
{
    public:
        enum myEnum
        {
            myEnum1,
            myEnum2
        };
};

I also declare a constructors, a public parameterized one as follows:

myClass(myEnum);

I define the same outside the classs definition as follows:

myClass :: myClass(myEnum E)
{
}

How do I initialise myEnum with default arguments?

I tried:

i) 

myClass :: myClass(myEnum E = 0); //to int error

ii)

myClass :: myClass(myEnum E = {0}); //some error

iii)

myClass :: myClass(myEnum E = {0, 1}); //some error

One thing I still don't seem to understand.

How do I pass enum values to the constructor. I still get an error. And, I need to do it this way:

derived(arg1, arg2, arg3, enumHere, arg4, arg5); //call

Function definition:

derived(int a, int b, int c, enumHere, int 4, int 5) : base(a, b);

Where am I supposed to initialise the enum, as one of the answers belowe do it?

Kuttu V
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    In my answer, I assumed it's c++, tags are not saying this, you could fix this, your question would gain much more attention then. – Bartosz Sep 23 '12 at 10:43
  • @Bartosz: It is indeed C++. Have changed the tags now. Thanks. – Kuttu V Sep 23 '12 at 11:02

1 Answers1

10

Seems like you've mistaken type declaration with field. In your class myEnum is declaration of type, and class itself does not hold any field of that type.

Try this:

class myClass
{
    public:
        enum myEnum
        {
            myEnum1,
            myEnum2
        } enumField;
};

Then, your constructor should use member initialization:

myClass::myClass() : enumField(myEnum1) {};

If you want parametrized constructor:

myClass::myClass(myEnum e) : enumField(e) {};

If you want parametrized constructor with default argument:

myClass(myEnum e = myEnum1) : enumField(e) {};

If you want to use aforementioned constructor in derived class:

myDerived(myEnum e) : myClass(e) {};
Bartosz
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