What's the limit of fraction inside square root

Question

I need to find limit sqrt((3x-1)/(x+2)) when x->infinity

Can anyone help me please?

I cannot get a rid of stupid fraction in the square root. -_- — Jan Vorisek, Sep 16 '12 at 12:28

score 2 · Answer 1 · edited Apr 13 '17 at 12:19

2

The answer is sqrt(3):

As x gets very very big, the degree 0 terms (-1x^0 and 2x^0) grow insignificant thus leaving:

sqrt(3x/x)

As you can see this reduces to:

sqrt(3)

And this is no longer affected by x and is, then, the answer.

Note

Math questions are best suited on Stack Exchange's Math page.

edited Apr 13 '17 at 12:19

Community

answered Sep 16 '12 at 12:31

mjgpy3

score 1 · Answer 2 · answered Sep 16 '12 at 12:36

1

mjgpy3 deserves credit for his correct and elegant explanation.

But I'll offer you Wolfram Alpha as a way to answer these for yourself without having to ask here:

answered Sep 16 '12 at 12:36

duffymo

2 Answers2