Does HttpsURLConnection.getInputStream() makes automatic retries?

Question

I am making a service request to a server using HttpsURLConnection like the code below :

URL url = new URL("service/url");
HttpsURLConnection connection = (HttpsURLConnection) url.openConnection();
connection.setConnectionTimeout(300000);
connection.setReadTimeout(300000);
parse (connection.getInputStream());

Service sometimes may take longer time, so ideally I should expect a TimeOut Exception but instead the client is making a retry and sending the same request again. Is there a way to explicitly disable any kind of retries? And I am not even sure if the set timeout methods are making any difference.

I am using Java 1.6

UPDATE
I tried connect() and getResponseCode() instead of getInputStream() but same behaviour:

URL url = new URL("service/url");
HttpsURLConnection connection = (HttpsURLConnection) url.openConnection();
connection.setConnectionTimeout(300000);
connection.setReadTimeout(300000);
connection.connect();
connection.getResponseCode();

even this is making 2 requests.

UPDATE
HttpClient fixed the issue. In HttpClient you can explicitly set retry to false

2 exactly same requests are coming up in the server logs. And request is failing due to duplicate request. — gnuger, Sep 11 '12 at 07:50
Please use a tool like [fiddler](http://www.fiddler2.com/fiddler2/) to check if this is a client side issue. — gammay, Sep 11 '12 at 07:57

score 2 · Answer 1 · answered Sep 11 '12 at 08:42

2

You shouldn't be calling openConnection() and connect(), just call openConnection().

answered Sep 11 '12 at 08:42

TedTrippin

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Does HttpsURLConnection.getInputStream() makes automatic retries?

1 Answers1