PHP equality - where am I going wrong?

Question

This is driving me nuts. Two integers should be equal.

<?php

function getPort() {
    return 443;
}

$port = getPort(); 
var_dump(433, $port, $port == 433, 443 == $port, 433 == 433);

?>

Result in both PHP 5.2 and 5.4:

int(433)
int(443)
bool(false)
bool(true)
bool(true)

In the previous code why does $port not equal 443 but 443 does equals $port? I must be doing something stupid surely?

Thanks for the second pair of eyes. Literally was stuck on that for ages. Embarrassing! — James Newell, Sep 05 '12 at 13:50

score 4 · Answer 1 · answered Sep 05 '12 at 12:53

4

Small typo:

once you compare 433 with $port and not 443!

$port == 433

vs

443 == $port

answered Sep 05 '12 at 12:53

Sirko

because 433 == 433 and 443 != 433 – p0rter Sep 05 '12 at 12:55
@Fluffeh because `433 == 433` is true? or you mean the third one? In that case `$port` is set to 443, which equals 443 as in the comparison. – Sirko Sep 05 '12 at 12:56
@MattHumphrey Yeah, got caught up with 443 :( Deleted question-Comment. +1'ed both answers. – Fluffeh Sep 05 '12 at 12:56

Matt Humphrey · Accepted Answer · 2012-09-05T12:58:35.597

3

Your doing $port == 433 in the first parameter and 443 in the second, and therefore it is correct.

So, to answer your question, yes; you are doing something stupid! ;)

edited Sep 05 '12 at 12:58

answered Sep 05 '12 at 12:53

Matt Humphrey

score 0 · Answer 3 · answered Sep 05 '12 at 12:55

0

You are setting 443 in $port and comparing with 433. This will always return false.

answered Sep 05 '12 at 12:55

Prashant

3 Answers3