Decimal to BASE-26 representation

Question

I wrote code to convert a decimal number to a corresponding alphabetical representation.

Examples:

1: A
2: B
.
.
.
26: Z
27: AA
.
.
.
703: AAA

Here is my approach:

void print(int n)
{
    if( n > 0 )
    {
        n--;
        print( n / 26 );
        printf( "%c", ( n % 26 ) + 'A' );
    }
}

The above code is working correctly. Can I optimize it in terms of readability?
What is the best way to do it?

Now, I want to modify the above code to work like this:

0: A
1: B
.
.
.
25: Z
26: AA
.
.
.
702: AAA

The obvious approach is to add 1 to the input decimal number and pass it to the function in the original code. How can I modify the first program to work it for the second case without adding 1?

You have a pretty odd idea how how base-26 would work; you seem to be missing a zero... — R.. GitHub STOP HELPING ICE, Sep 02 '12 at 16:19
@R.. Please look at the code carefully. Its not converting to Base 26. Observe n-- — Green goblin, Sep 02 '12 at 17:03
I meant the example, not the code. If the base is 26, there should not be a symbol (Z) with value 26... — R.. GitHub STOP HELPING ICE, Sep 02 '12 at 17:13

score 1 · Accepted Answer · answered Sep 02 '12 at 17:24

1

After some observations, i have tried the below code & its working for the Case: 2.

void print(int n)
{
    if(n < 26)
        printf("%c", n + 'A');
    else
    {
        print(n / 26 - 1);

        print(n % 26);
    }
}

See output here.

answered Sep 02 '12 at 17:24

Green goblin

9,898
13
71
100

Decimal to BASE-26 representation

1 Answers1