Python SocketServer.BaseRequestHandler wont communicate to remote requests

Question

I've been developing Python server using SocketServer.TCPServer and SocketServer.BaseRequestHandler base classes. I'm using host "localhost" and port 2304 (not used by any other program).

The problem is that my server wont respond to remote request. I'm using Amazon AWS and have an static IP address for access.

When I test the server on the Amazon local machine using eg. browser, I see that my server does it's stuff, but remote access stays blocked. No clue how to open 2304 port to be accessible from outside local machine.

Here is the whole code:

import threading, socket
import SocketServer, Queue
import globals
import transaction_pool


class CTSRSThreadedTCPRequestHandler(SocketServer.BaseRequestHandler):

    def handle(self):

        if globals.terminating:
            self.Respond("")


        pCurrThread = threading.currentThread()
        sData = self.request.recv(8192)

        print "CTSRSThreadedTCPRequestHandler->RECV->OK!"

        sResponse = "OK!"

        self.Respond(sResponse)

        print "CTSRSThreadedTCPRequestHandler->SEND->OK!"

    #-------------------------------------------------------------------------

    def Respond(self, sResponse):
        self.request.send(sResponse)

    #-------------------------------------------------------------------------


class CTSRSThreadedTCPServer(SocketServer.ThreadingMixIn, SocketServer.TCPServer):
    allow_reuse_address = True


class CTSRSServer:

    m_pServerThread = None
    m_pServer = None

    #----------------------------------------------------------

    def StartServer(self):
        try:
            self.m_pServer = CTSRSThreadedTCPServer(("localhost", 2304), CTSRSThreadedTCPRequestHandler)
            sIP, iPort = self.m_pServer.server_address

            self.m_pServerThread = threading.Thread(target = self.m_pServer.serve_forever)

            self.m_pServerThread.daemon = True
            self.m_pServer.daemon_threads = True
            self.m_pServerThread.start()

            globals.system_log.info("[CTSRS]->StartServer()")

        except Exception, e:
            globals.system_log.info("[CTSRS]->StartServer() -> Exception: " + str(e))
            return False

        return True


    #----------------------------------------------------------

    def StopServer(self):
        globals.system_log.info("[CTSRS]->StopServer()")

    #----------------------------------------------------------

score 4 · Accepted Answer · answered Sep 02 '12 at 07:40

4

Of course it wont respond to remote requests, "localhost" means exactly what it says, it's the "local host". You have to bind to the external interface instead, or to the generic "catch-all" interface.

To bind to all interfaces use e.g.

self.m_pServer = CTSRSThreadedTCPServer(('', 2304), CTSRSThreadedTCPRequestHandler)

The empty string as the address makes the server listen on all interfaces.

answered Sep 02 '12 at 07:40

Some programmer dude

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How do I bind it to generic "catch-all" interface? – StjepanV Sep 02 '12 at 07:45
Thanks mr. Pileborg! Works great! – StjepanV Sep 02 '12 at 07:47

score 1 · Answer 2 · answered Sep 02 '12 at 07:33

1

Try listen at "127.0.0.1:2304":

self.m_pServer = CTSRSThreadedTCPServer(("127.0.0.1", 2304), CTSRSThreadedTCPRequestHandler)

answered Sep 02 '12 at 07:33

SKGOD

19
1

Thanks for the reply, but localhost translates to 127.0.0.1. I've tried it for the heck of it, but still the same effect :( – StjepanV Sep 02 '12 at 07:35
3

Try ip address blank。self.m_pServer = CTSRSThreadedTCPServer(("", 2304), CTSRSThreadedTCPRequestHandler) – SKGOD Sep 02 '12 at 07:39

Python SocketServer.BaseRequestHandler wont communicate to remote requests

2 Answers2