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I have got a problem with addressing in x86. Can someone tell me what this does:

mov 4000(%ecx, %ebx, 4), %eax
Bo Persson
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user1527017
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1 Answers1

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An address is computed as 4000 plus the value in the %ecx register plus 4 times the value in the %ebx register. A 32-bit value is loaded from that address and put into the %eax register.

Alan Curry
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    I find Intel syntax more intuitive that AT&T regards to addressing. In Intel syntax `mov 4000(%ecx, %ebx, 4), %eax` would be `mov eax,[ecx+4*ebx+4000]`. – nrz Aug 26 '12 at 06:17