On EditText Changed Listener, Integer.parseInt() does not work

Question

when adding the line of parsing the text to integer the app stops, and it works well without this line

final TextView secNumber= (TextView)findViewById(R.id.secNumber);
final EditText mainNumber=(EditText)findViewById(R.id.mainNumber);

mainNumber.addTextChangedListener(new TextWatcher(){
    public void afterTextChanged(Editable S){
        secNumber.setText(Integer.parseInt(S.toString())*100);
    }

    public void beforeTextChanged(CharSequence arg0, int arg1, int arg2,
            int arg3) {
        // TODO Auto-generated method stub

    }

    public void onTextChanged(CharSequence s, int start, int before,
            int count) {
        // TODO Auto-generated method stub

    }
});

score 1 · Answer 1 · answered Aug 17 '12 at 03:26

1

Try this:

 secNumber.setText((Integer.parseInt(S.toString())*100).toString());

answered Aug 17 '12 at 03:26

JiTHiN

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score 0 · Answer 2 · edited May 23 '17 at 12:27

0

You need to find out what's in S. Apparently, it's not parseable. Wrap the parseInt operation in a try catch block, or use a "TryParse", as illustrated here.

edited May 23 '17 at 12:27

Community

1
1

answered Aug 16 '12 at 22:18

Robert Harvey

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Can you be more specific? I didn't really expect it to parse `S`, since what is in `S` is already not parseable. – Robert Harvey Aug 16 '12 at 22:29
the application stops again when using a "TryParse", as illustrated above. there was no difference – Mira Aug 16 '12 at 22:35

score 0 · Answer 3 · edited Jan 07 '14 at 14:21

0

You are giving a Integer for secNumber.setText( Integer) and the function probably needs a String. Put a toString() at end.

Try something like that

Integer  pipi= Integer.parseInt(S.toString())*100);
secNumber.setText(pipi.toString());

edited Jan 07 '14 at 14:21

kleopatra

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answered Jan 07 '14 at 14:14

Alejandro

1

On EditText Changed Listener, Integer.parseInt() does not work

3 Answers3