Pyramids route_url with additional query arguments

Question

In Pyramids framework, functions route_path and route_url are used to generate urls from routes configuration. So, if I have route:

config.add_route('idea', 'ideas/{idea}')

I am able to generate the url for it using

request.route_url('idea', idea="great");

However, sometimes I may want to add additional get parameters to generate url like:

idea/great?sort=asc

How to do this?

I have tried

request.route_url('idea', idea='great', sort='asc')

But that didn't work.

score 34 · Accepted Answer · edited Apr 03 '14 at 14:02

34

You can add additional query arguments to url passing the _query dictionary

request.route_url('idea', idea='great', _query={'sort':'asc'})

edited Apr 03 '14 at 14:02

Wilfred Hughes

answered Aug 16 '12 at 14:25

Samuel Hapak

2

if you're answering your own question you have no excuse to not accept it ;-) – Michael Merickel Aug 16 '12 at 19:41

score 5 · Answer 2 · answered Jan 22 '14 at 17:28

5

If you are using Mako templates, _query={...} won't work; instead you need to do:

${request.route_url('idea', idea='great', _query=(('sort', 'asc'),))}

The tuple of 2-tuples works as a dictionary.

answered Jan 22 '14 at 17:28

labreuer

1

I'm using mako and _query { ... } worked just fine, perhaps you can tell us why it won't work? – CrackSmoker9000 Oct 10 '14 at 21:10
@SSIgnatzSchönborn: Did you enclose your `_query { ... }` with `${}`? It seemed that Mako templates would not do nested braces. Perhaps a new version has remedied that? I could try a repro if necessary, although I haven't touched Mako in a while. – labreuer Oct 14 '14 at 18:27

2 Answers2