Python - Add seconds to time object

Question

I have a time object which looks like this:

time.struct_time(tm_year=2012, tm_mon=8, tm_mday=11, tm_hour=18, tm_min=48, tm_sec=23, tm_wday=5, tm_yday=224, tm_isdst=0)

I was wondering if there was an easy way add seconds to it.

I want to add 4497 seconds to it.

I've previously tried to convert each individual component to seconds and add them.

Thanks,

Parth

Note that if you can use the [`datetime` module](http://docs.python.org/library/datetime.html) instead, this is as simple as `old_datetime + datetime.timedelta(seconds=4497)`. — Danica, Aug 11 '12 at 23:12

icktoofay · Accepted Answer · 2012-08-11T23:49:37.747

Note: This answer applies to an old version of the question asking how to convert a time.struct_time into an int representing seconds and does not answer what the question currently asks (how to add a number of seconds to a time.struct_time).

Assuming you want to convert to seconds since January 1, 1970, you can use:

time.mktime for local time.
calendar.timegm for UTC time.

These conversions (and their inverses) are detailed in the documentation for the time module.

Python - Add seconds to time object

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