In Java, we can convert an int to float implicitly, which may result in loss of precision as shown in the example code below.
public class Test {
public static void main(String [] args) {
int intVal = 2147483647;
System.out.println("integer value is " + intVal);
double doubleVal = intVal;
System.out.println("double value is " + doubleVal);
float floatVal = intVal;
System.out.println("float value is " + floatVal);
}
}
The output is
integer value is 2147483647
double value is 2.147483647E9
float value is 2.14748365E9
What is the reason behind allowing implicit conversion of int to float, when there is a loss of precision?