Defualt id generated by Eclipse has char inside the value, and the variable type is long. How?

Question

This is not new, but I wonder how come java can assign something like, 1L to long datatype.

private static final long serialVersionUID = 1L;

where the definition of long data type is,

long: The long data type is a 64-bit signed two's complement integer. It has a minimum value of -9,223,372,036,854,775,808 and a maximum value of 9,223,372,036,854,775,807 (inclusive). Use this data type when you need a range of values wider than those provided by int.

From : Oracle, Java primitive datatypes

Well, `L` means that you're giving it a long literal... – Dennis Meng Aug 10 '12 at 00:09 — Dennis Meng, Aug 10 '12 at 00:09

score 3 · Accepted Answer · answered Aug 10 '12 at 00:09

3

The L indicates that it is a long. In other words, 1 is an int whereas 1L is a long. It is specified in the Java Language Specification #3.10.1:

An integer literal is of type long if it is suffixed with an ASCII letter L or l (ell); otherwise it is of type int.
The suffix L is preferred, because the letter l (ell) is often hard to distinguish from the digit 1 (one).

answered Aug 10 '12 at 00:09

assylias

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Huh, I could've sworn there was a specifier for making it a short. I guess I was wrong? – Dennis Meng Aug 10 '12 at 00:12
If by short you mean a "normal" int, then there no specifier (AFAIK). – assylias Aug 10 '12 at 00:14
By short I meant the data type. – Dennis Meng Aug 10 '12 at 00:15
@DennisMeng I guess I'm tired! No there does not seem to be any specifiers for short. – assylias Aug 10 '12 at 00:19

Defualt id generated by Eclipse has char inside the value, and the variable type is long. How?

1 Answers1