Django: Filtering drafts by user causes error

Question

I'm trying to filter through a set of drafts objects in a database using the request.user variable. They are For some reason I get the error listed bellow. How can I fix this bug?

Function:

def posting_draft(request):
    user = request.user
    user_drafts = Draft.objects.filter(user = user)
    drafts = dict()
    for d in user_drafts:
        drafts[d.title] = d.id
    return render_to_response('posting_draft.html', {'STATIC_URL':STATIC_URL, 'draft_l' : drafts})

Error:

int() argument must be a string or a number, not 'SimpleLazyObject'

It would be helpful if you included the rest of your traceback. — stderr, Aug 09 '12 at 02:54

score 4 · Accepted Answer · answered Aug 09 '12 at 03:00

4

Since request.user is a SimpleLazyObject until it is accessed. Try changing your query to the following:

user_drafts = Draft.objects.filter(user = user.pk)

answered Aug 09 '12 at 03:00

Matt Williamson

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Could you explain what .pk does? – sinθ Aug 09 '12 at 03:10
1

It's the same as `user.id`, but will work even if you have a different field set as the `primary_key`. When you call it, it will force the `SimpleLazyObject` to become populated. It does the so that the data will only be fetched from the DB if you really need it, since DB lookups are relatively expensive. – Matt Williamson Aug 09 '12 at 03:13

score 3 · Answer 2 · edited May 23 '17 at 12:20

3

The problem is in the line:

user = request.user

Read this post for more details request.user returns a SimpleLazyObject, how do I "wake" it?

edited May 23 '17 at 12:20

Community

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answered Aug 09 '12 at 02:36

codegeek

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Django: Filtering drafts by user causes error

2 Answers2

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