PHP get a part of a array using function

Question

I have an array like this:

$a1 = array(
    array('id'=>"1","others"=>"asdhuisah"),
    array('id'=>"4","others"=>"asdhuisah"),
    array('id'=>"213","others"=>"asdhuisah")
);

and I want to save a part of it into a new array $a2.

I know I can do it using loops:

$a2 = array();
foreach($a1 as $key=>$value){
    array_push($a2,$value["id"]);
}

Is there a function that I can use to do all this at once?

Did you check here? http://fr.php.net/manual/en/ref.array.php — Jocelyn, Aug 06 '12 at 01:36
The function you are looking for is called [`array_column`](http://stackoverflow.com/a/11558780/367456). — hakre, Aug 06 '12 at 01:37

score 0 · Accepted Answer · answered Aug 06 '12 at 01:42

0

Try this:

$fun_id = function($value){

    return $value["id"];

} ;

$a2 = array_map($fun_id, $a1);

answered Aug 06 '12 at 01:42

levi

thanks your code does work. I mean is there a function in PHP, not user definded function. – v-joy Aug 06 '12 at 01:44
@v-joy The answer to that question is simply "no" at this point in time. – Chris Trahey Aug 06 '12 at 01:46
No, there is no such built-in function. As mentioned in the thread hakre linked to, it has been proposed for PHP 5.5. – Barmar Aug 06 '12 at 01:46
there is not, but that way is clean and elegant. – levi Aug 06 '12 at 01:49
Array_slice can do it I think – artragis Aug 11 '12 at 13:05

score 0 · Answer 2 · answered Aug 06 '12 at 01:44

0

You can use array_map and a lambda function:

$return_id = function($item) {
  return $item['id'];
};
$ids_array = array_map($return_id, $a1);

answered Aug 06 '12 at 01:44

Chris Trahey

I am wondering if there is a buildin function witch can do this job. but thanks for your help. – v-joy Aug 06 '12 at 02:01

score 0 · Answer 3 · answered Aug 11 '12 at 13:04

0

answered Aug 11 '12 at 13:04

artragis

3 Answers3