execvp does not get argument

Question

My code is:

execvp(command, args);

args is char* args[]

command is char* command

for example for ls -l, command is ls and args is -l but why after executing

execvp(command, args)I get only result of ls not ls -l??

Answer 1

The argument list also contains the name of the program. Make sure that your args array contains both "ls" and "-l".