I am having problems trying to get the following XSLT template for the DotNetNuke DDRMenu to spit out the last page/node of the breadcrumb for the following conditions:
- the last page is NOT "Include(d) in the Menu" in its page settings
- however the last page is a child of the the parent node (which does show up in my output)
How do I get the page not included in the menu to be outputted at the end of my breadcrumb from the following XSL template?:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:param name="separator"></xsl:param>
<xsl:template match="/*">
<xsl:apply-templates select="root" />
</xsl:template>
<xsl:template match="root">
<ul>
<xsl:apply-templates select="//node[@breadcrumb=1]" />
</ul>
</xsl:template>
<xsl:template match="node">
<li>
<xsl:choose>
<xsl:when test="@enabled = 1">
<a href="{@url}" title="{@title}">
<xsl:value-of select="@text" />
</a>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="@text" />
</xsl:otherwise>
</xsl:choose>
</li>
</xsl:template>
</xsl:stylesheet>
