Made numeric decrement

Question

anybody can help me me with this? I have a variable such:

$page = '50';
$newpage = 'http://www.mydomain.com/page/'.$page.'';

I want new page echo such this:
http://www.mydomain.com/page/50
http://www.mydomain.com/page/49
......
.......
....... until page acho such:
http://www.mydomain.com/page/1

Open your php documentation, see chapter about operators (and type casting if necessary) and loop. Or at least post what you have done. — LeleDumbo, Jul 30 '12 at 21:09
This is... incredibly, incredibly basic [`for`](http://php.net/manual/en/control-structures.for.php) looping. — Palladium, Jul 30 '12 at 21:15
If you can't do a basic `for` loop then you really need to start with some basic tutorials/a book. — williamvicary, Jul 30 '12 at 21:49

score 2 · Answer 1 · answered Jul 30 '12 at 21:18

2

<?php
for($page=50;$page>0;$page--) {
    $newpage = 'http://www.mydomain.com/page/'.$page.'';
    echo "$newpage\n";
}
?>

answered Jul 30 '12 at 21:18

j08691

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score 1 · Answer 2 · answered Jul 30 '12 at 21:17

Look at this for loop:

$prefix = 'http://www.mydomain.com/page/';
for ($page = 50; $page >= 1; $page--) {
    echo $prefix.$page;
}

First, the variable $page is initialized. I use 50 instead of '50' because we're dealing with numbers and not with strings.

The next bit is the condition while the loop continues: $page >= 1 - so the loop will stop after 1.

The last part is a decrement operator, it subracts 1 off $page for each loop iteration.

Finally, the prefix and the page number are combined using the concat operator (.).

score 0 · Answer 3 · answered Jul 30 '12 at 21:18

What you are looking for is :

<?php
for($i=50; 0 <= $i; $i--){
    echo $i.'<br />';
}
?>

if you don't want to go upto 0, change <= for <. This will loop from 50 until 0 so it will eacho in order :

Here 50 is your start number, 0 is your last number to go. So in this example it print out 50 until 0.

Made numeric decrement

3 Answers3