How to convert back to transfer function in Maple?

Question

using DiffEquation can transform to diff sys, but if convert back to transfer function, How is it?

with(DynamicSystems):
sys2 := DiffEquation(sqrt(1-a^2)/(1-a/s));
PrintSystem(sys2);

de := [Diff(x1(t),t) = a*x1(t)+a*u1(t), y1(t) = sqrt(1-a^2)*x1(t)+sqrt(1-a^2)*u1(t)];

score 0 · Accepted Answer · answered Jul 22 '12 at 03:33

I'm not sure that I understand the phrasing of your question. Is this the sort of thing that you want?

with(DynamicSystems):

sys2 := DiffEquation(sqrt(1-a^2)/(1-a/s)):

sys2:-de;

        [                               
        [ d                             
        [--- x1(t) = a x1(t) + a u1(t), 
        [ dt                            

                          (1/2)                 (1/2)      ]
                  /     2\              /     2\           ]
          y1(t) = \1 - a /      x1(t) + \1 - a /      u1(t)]
                                                           ]

K:=TransferFunction(sys2):

K:-tf;

                  [         (1/2)         (1/2)  ]
                  [  (a + 1)      (-a + 1)      s]
                  [- ----------------------------]
                  [             -s + a           ]

expand(combine(K:-tf[1,1])) assuming a>0;

                                    (1/2)  
                            /     2\       
                            \1 - a /      s
                          - ---------------
                                -s + a

How to convert back to transfer function in Maple?

1 Answers1