2

I am try for role based access in spring but got the following error:- 

Caused by: org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'http'.
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:195)
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.error(ErrorHandlerWrapper.java:131)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:384)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:318)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator$XSIErrorReporter.reportError(XMLSchemaValidator.java:410)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.reportSchemaError(XMLSchemaValidator.java:3165)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.handleStartElement(XMLSchemaValidator.java:1898)
at com.sun.org.apache.xerces.internal.impl.xs.XMLSchemaValidator.startElement(XMLSchemaValidator.java:685)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:400)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:2740)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:647)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:140)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:508)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:807)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:737)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:107)

And here is my spring-security.xml:

<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">

<http auto-config="true">
    <intercept-url pattern="/welcome*" access="ROLE_USER" />
    <form-login login-page="/login" default-target-url="/welcome"
        authentication-failure-url="/loginfailed" />
    <logout logout-success-url="/logout" />
</http>

<authentication-manager>
    <authentication-provider>
        <user-service>
            <user name="a" password="1" authorities="ROLE_USER" />
        </user-service>
    </authentication-provider>
</authentication-manager>

</beans:beans>
Tarun Gupta
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  • Tarun, How did you resolve the issue? Please share your solution. – Atul Jul 18 '12 at 07:01
  • I am try role based security in spring but getting error during compilation. Please provide the suitable solution for that...... – Tarun Gupta Jul 31 '12 at 05:44
  • You are probably just missing spring-security-config jar. See also:http://stackoverflow.com/questions/10561579/the-matching-wildcard-is-strict-but-no-declaration-can-be-found-for-element-h – Ravi Kadaboina Aug 02 '12 at 17:33

2 Answers2

2

Seems, the required library files for Spring Security aren't at right place. Are you using Maven and have maven dependency of Spring Security library files in your pom.xml file?

If it is then do a maven clean-up and have a try again. Otherwise you can place Spring security library files in the class-path directly.

Arun Kumar
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0

Please check if application has the necessary spring security library files in the classpath (if you are using Maven, check pom.xml file). Also, check for other Spring related xml files for syntax errors (or please post them also).

Irmak Cakmak
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