How to judge a variable's type as string or integer

Question

This is my code:

if [ $value == "^[[:digit:]]*$" ]
then
    echo "number"
else
    echo "other"
fi

It seems that the program never echoes "number" even if I set value=1.

score 7 · Accepted Answer · answered Jul 17 '12 at 05:44

7

test doesn't do regexs.

[[ $value =~ ^[0-9]+$ ]]

answered Jul 17 '12 at 05:44

2

+1 Beat me to it. Also important is that the OP needs to not have quotes around the regex. Plus the question was missing a `then` ... – Ray Toal Jul 17 '12 at 05:46
could I ask that what `~` refers to? – iverson Jul 17 '12 at 06:26
1

Short answer: =~ is a distinct operator, just like == and != – chepner Jul 17 '12 at 12:23

1 Answers1