9

I have a for loop which returns an array.

Return:

1st loop:
arr[0]
arr[1]
arr[2]
arr[3]

Here the length I get is 4 (Not a problem).

Return:

2nd loop
arr[4]
arr[5]
arr[6]
arr[7] 
arr[8] 

Here the length I get is 9.

What I want here is the actual count of the indexes i.e I need it to be 5. How can I do this. And is there a way that when I enter each loop every time it starts from 0 so that I get proper length in all the loops?

Massifox
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Adnan Baliwala
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4 Answers4

39

This is easily done natively using Array.filter:

resetArr = orgArr.filter(function(){return true;});
Dag Sondre Hansen
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4

You could just copy all the elements from the array into a new array whose indices start at zero.

E.g.

function startFromZero(arr) {
    var newArr = [];
    var count = 0;

    for (var i in arr) {
        newArr[count++] = arr[i];
    }

    return newArr;
}

// messed up array
x = [];
x[3] = 'a';
x[4] = 'b';
x[5] = 'c';

// everything is reordered starting at zero
x = startFromZero(x);
danmcardle
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  • i love you crazedgremlin..you made my day – Adnan Baliwala Jul 10 '12 at 14:15
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    You're welcome! Just so you know, this is a bad solution to your problem -- you should probably choose a new data structure such as a linked list that will allow you to delete items without having to recreate the array each time. Also, you should choose an answer if you have found a solution to your problem! – danmcardle Jul 10 '12 at 14:42
4

Easy,

var filterd_array = my_array.filter(Boolean);
M_R_K
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3

Perhaps "underscore.js" will be useful here.

The _.compact() function returns a copy of the array with no undefined.

See: http://underscorejs.org/#compact

ata
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hallodom
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