iOS SBJsonWriter returns null

Question

I´m using the SBJson framework the first time, and I´ve got a big problem, the following code always returns null. The NSDictionary is correctly filled (I printed every value out!).

NSDictionary *nsDictionary = [NSDictionary dictionaryWithObjects:values forKeys:keys];
SBJsonWriter *jsonWriter = [[SBJsonWriter alloc] init];
NSString *jsonString = [jsonWriter stringWithObject:nsDictionary];
NSLog(@"%@", jsonString);

I also tried this:

NSDictionary *nsDictionary = [NSDictionary dictionaryWithObjects:values forKeys:keys];
SBJsonWriter *jsonWriter = [SBJsonWriter new];
NSString *jsonString = [jsonWriter stringWithObject:nsDictionary];
NSLog(@"%@", jsonString);

Have you validated that the JSON you're parsing is valid? Use http://jsonlint.com/ to validate, also consider using http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSJSONSerialization_Class/Reference/Reference.html instead of SBJSONParser — Devraj, Jul 09 '12 at 09:45
I can´t use apple´s framework because my app must be compatible with iOS 4.X >. — , Jul 09 '12 at 09:48

score 2 · Accepted Answer · answered Jul 09 '12 at 10:09

2

The dictionary may contains objects that cannot be written by SBJsonWriter.

You may use -[SBJsonWriter stringWithObject:error:] to get the failure's reason.

NSDictionary *nsDictionary = [NSDictionary dictionaryWithObjects:values forKeys:keys];
SBJsonWriter *jsonWriter = [SBJsonWriter new];
NSError *error = nil;
NSString *jsonString = [jsonWriter stringWithObject:nsDictionary error:&error];
if ( ! jsonString ) {
    NSLog(@"Error: %@", error);
}

answered Jul 09 '12 at 10:09

Nicolas Bachschmidt

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1

Thanks, SBJsonWriter can't handle NSDate – Jul 09 '12 at 10:45
2

Converting an NSDate to a double is a good fix for JSON format: @([date timeIntervalSince1970]) – pokstad Sep 08 '12 at 17:56

iOS SBJsonWriter returns null

1 Answers1