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I am trying to smoothen my hand drawn Bezier curves, but not able to achieve, it, I got the code of smoothing the curve from the book written by erica sudan , which I tried to implement , but dont know why I am not able to produce a smooth curve, below is my code , I request all of you to please go through it ..

- (void)drawRect:(CGRect)rect
{    
     myPath.pathColor = [UIColor redColor];         

    for (BezeirPath *_path in m_pathArray) 
    {
        [_path.pathColor setStroke];
        [_path.bezeirPath strokeWithBlendMode:kCGBlendModeNormal alpha:1.0];         

    }   
}   

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event
{

     UITouch *mytouch=[[touches allObjects] objectAtIndex:0];

    m_previousPoint1 = [mytouch previousLocationInView:self];
    m_previousPoint2 = [mytouch previousLocationInView:self];
    m_currentPoint   =  [mytouch locationInView:self];


    CGPoint controlPoint = CGPointMake(m_previousPoint1.x+(m_previousPoint1.x - m_previousPoint2.x), m_previousPoint1.y +(m_previousPoint1.y - m_previousPoint2.y));
    [myPath.bezeirPath addQuadCurveToPoint:m_currentPoint controlPoint:controlPoint];    
    self.previousPoint3 = controlPoint; 

    [myPath.bezeirPath smoothedPath:myPath.bezeirPath :40];//Called the smoothing function.

   [self setNeedsDisplay];
}

//Smoothing function

-(UIBezierPath*)smoothedPath:(UIBezierPath*)bpath: (NSInteger) granularity
{
    NSArray *points = pointsFromBezierPath(bpath);
    if (points.count < 4) return bpath;
    // This only copies lineWidth. You may want to copy more
    UIBezierPath *smoothedPath = [UIBezierPath bezierPath];
    smoothedPath.lineWidth = bpath.lineWidth;
    // Draw out the first 3 points (0..2)
    [smoothedPath moveToPoint:POINT(0)];
    for (int index = 1; index < 3; index++)
        [smoothedPath addLineToPoint:POINT(index)];
    // Points are interpolated between p1 and p2,
    // starting with 2..3, and moving from there
    for (int index = 4; index < points.count; index++)
    {
        CGPoint p0 = POINT(index - 3);
        CGPoint p1 = POINT(index - 2);
        CGPoint p2 = POINT(index - 1);
        CGPoint p3 = POINT(index);
        // now add n points starting at p1 + dx/dy up until p2
        // using Catmull-Rom splines
        for (int i = 1; i < granularity; i++)
        {
            float t = (float) i * (1.0f / (float) granularity);
            float tt = t * t;
            float ttt = tt * t;
            CGPoint pi; // intermediate point
            pi.x = 0.5 * (2*p1.x+(p2.x-p0.x)*t +
                          (2*p0.x-5*p1.x+4*p2.x-p3.x)*tt +
                          (3*p1.x-p0.x-3*p2.x+p3.x)*ttt);
            pi.y = 0.5 * (2*p1.y+(p2.y-p0.y)*t +
                          (2*p0.y-5*p1.y+4*p2.y-p3.y)*tt +
                          (3*p1.y-p0.y-3*p2.y+p3.y)*ttt);
            [smoothedPath addLineToPoint:pi];
        }

        [smoothedPath addLineToPoint:p2];
    }
    // finish by adding the last point
    [smoothedPath addLineToPoint:POINT(points.count - 1)];
    return smoothedPath;
}
alecail
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Ranjit
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1 Answers1

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I suggest watching "Building Advanced Gesture Recognizers" from WWDC 2012. You can skip the beginning - the part you are most interested in is at 38:23.

futurevilla216
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  • Hey thanks @Lenny K for replying, I skipped my approach of using BezeirPaths because of performance issues? What you have to say about my decision? please reply – Ranjit Jul 10 '12 at 13:55
  • What did you decide to use instead? – futurevilla216 Jul 10 '12 at 13:56
  • I am using CgContex and its related functions and Cglayer to cache the drawing – Ranjit Jul 10 '12 at 14:00
  • OK. Unfortunately, I don't know too much about this topic, so I can't give you a good suggestion. – futurevilla216 Jul 10 '12 at 14:02
  • No, unfortunately the only thing I know on the topic is from the video I mentioned above. – futurevilla216 Jul 10 '12 at 14:06
  • Ok, anyways thanks, actually I have completed the drawing part, but stuck with undo and redo functionalities, check out this link http://stackoverflow.com/questions/11394839/undo-redo-issues-with-cglayer. If you know some one who can comment on this link, please ask him to do, I will be thankful to you :) – Ranjit Jul 10 '12 at 14:09