Here is an example of how to copy/transfer files using C/C++ in Linux.The server
listens in port 8080. The client
transmits a filename. The server
receives the filename, open the file and sends its contents to the client. I intentionally used odd or small buffer sizes for illustrative purposes.
The server.c
file:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#include <netinet/in.h>
#include <unistd.h>
#include <fcntl.h>
int main (int argc,char *argv[])
{
struct sockaddr_in p;
struct sockaddr_in q;
int z,s,t,x,n,b = sizeof(q);
char buf[23];
int fd;
s = socket(AF_INET,SOCK_STREAM,0);
bzero (&p,sizeof(p));
p.sin_family = AF_INET;
p.sin_addr.s_addr = INADDR_ANY;
p.sin_port = htons(8080);
bind (s,(struct sockaddr*)&p,sizeof(p));
listen(s,13);
while (1) {
t = accept (s,(struct sockaddr*)&q, &b);
n = read(t,buf,23);
buf[n] = 0;
printf("%s sent: ",buf);
fd = open (buf,O_RDONLY);
z = lseek(fd,0,SEEK_END);
lseek(fd,0,SEEK_SET);
x = 0;
do {
n = read (fd,buf,23);
write (t,buf,n);
x += n;
} while (x < z);
printf("%d/%d\n",x,z);
close(fd);
close(t);
}
}
The client.c
file:
#include <stdio.h>
#include <string.h>
#include <netdb.h>
#include <unistd.h>
#include <fcntl.h>
void main (int argc, char *argv[])
{
int ret;
char buf[5];
int s,n,fd;
struct sockaddr_in p;
struct hostent *h;
char *str = argv[1];
fd = open (str,O_CREAT | O_WRONLY,S_IRUSR|S_IWUSR);
h = gethostbyname("127.0.0.1");
bzero(&p,sizeof(p));
p.sin_family = AF_INET;
p.sin_addr.s_addr = htonl(INADDR_ANY);
p.sin_addr.s_addr = ((struct in_addr*)(h->h_addr))->s_addr;
p.sin_port = htons(8080);
s = socket (AF_INET,SOCK_STREAM,0);
connect (s,(void*)&p,sizeof(p));
n = write (s,str,strlen(str));
int idx = 0;
do {
n = read (s,buf,5);
idx += n;
printf(".");
fflush(stdout);
write (fd,buf,n);
} while (n > 0);
close (fd);
close (s);
}
To compile:
- Open terminal
- gcc -o server server.c
- gcc -o client client.c
Run the server as ./server
. And then to copy rngoidiot.txt
, run the client as ./client rngoidiot.txt
and the file will be copied using TCP/IP. Simple combination ;-)