Regex for matching digits followed by . (dot) then digits followed by . and so on

Question

Currently I have this regex: [\d\.]+ I'm testing it with Regex Hero. You can check it working here.

It correctly reports 5 matches for these values:

1.1.4.3.
11.1.2.4.4.4.5
2
4.4
2.1.1

The problem is that it also matches the final . in the first value 1.1.4.3.

How can I exclude this last . and only match the value 1.1.4.3?

score 4 · Accepted Answer · answered Jun 28 '12 at 15:54

4

^\d+(\.\d+)*$

Should work, assuming two consecutive .s aren't allowed. Otherwise, just change the \. to \.+.

answered Jun 28 '12 at 15:54

Ry-

I voted for you in the moderator election... and I'll vote again in the next one. :) You're a great guy... can I say a super smart one. Keep helping and you'll learn more and more because is giving that we receive. There's no limit for knowledge. – Leniel Maccaferri Jun 30 '12 at 00:47

Justin Morgan - On strike · Answer 2 · 2012-06-28T18:47:32.287

1

It sounds like you want:

@"^(\d+\.)*\d+$"

edited Jun 28 '12 at 18:47

answered Jun 28 '12 at 15:54

Thanks Justin... but this one won't catch `1.2.12` for example. Off-topic: I really like when you say "On a really good day, it'll be Brazil." in your SO profile! :D – Leniel Maccaferri Jun 28 '12 at 16:03
@TimPietzcker - D'oh, I forgot that last `+`. My bad. Edited. – Justin Morgan - On strike Jun 28 '12 at 18:49
1

@LenielMacaferi - O Brasil, meu pais favorito no mundo! Rio and Curitiba in particular. Cheers. – Justin Morgan - On strike Jun 28 '12 at 18:53

2 Answers2