I have the following bash script, we can call it script1.sh
:
#!/bin/bash
exec ./script2.sh &
sleep 5
if job1 is alive then #<--- this line is pseudo-code!
exec ./script3.sh &
wait
fi
As can be seen, the script executes script2.sh
as a background job and then waits 5 seconds (so script2.sh
can do some initialization stuff). If the initialization succeeds, the script2.sh
job will still be alive, in which case I also want to start script3.sh
concurrently; if not, I just want to quit.
However, I do not know how to check whether the first job is alive, hence the line of pseudo-code. So, what should go in its place?