PHP Get all numerical/anonymous keys in an array

Question

I have a multidimensional array, I am interested in getting all the elements (one level deep) that don't have named keys.

i.e.

Array
{
  ['settings'] {...}
  ['something'] {...}
  [0] {...} // I want this one
  ['something_else'] {...}
  [1] {...} // And this one
}

Any ideas? Thanks for your help.

ian.shaun.thomas · Accepted Answer · 2012-06-20T16:13:55.193

6

This is one way

foreach (array_keys($array) as $key) {
 if(is_int($key)) {
  //do something
 }
}

EDIT

Depending on the size of your array it may be faster and more memory efficient to do this instead. It does however require that the keys are in order and none are missing.

for($i=0;isset($array[$i]);$i++){
 //do something
}

edited Jun 20 '12 at 16:13

answered Jun 20 '12 at 16:01

ian.shaun.thomas

3,468
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awesome that worked thanks for your help :) (will accept when i can) – Dominic Jun 20 '12 at 16:03

score 1 · Answer 2 · answered Jun 20 '12 at 16:01

1

$result = array();
foreach ($initial_array as $key => $value)
  if ( ! is_string( $key ) )
    $result[ $key ] = $value;

answered Jun 20 '12 at 16:01

linepogl

9,147
4
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thanks that should also work but tecent answered first - thanks anyway – Dominic Jun 20 '12 at 16:04

score 0 · Answer 3 · answered Jun 20 '12 at 16:00

0

The key is 0, Shouldn't be $your_array[0]?

answered Jun 20 '12 at 16:00

xdazz

158,678
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Yep but I could have many of these elements mixed in with named ones and I am unsure how many – Dominic Jun 20 '12 at 16:00

PHP Get all numerical/anonymous keys in an array

3 Answers3