c# Openfiledialog

Question

When I open a file using this code

if (ofd.ShowDialog() == DialogResult.OK)
     text = File.ReadAllText(ofd.FileName, Encoding.Default);

A window appear and ask me to choose file (The File Name is blank as you can see on the image)

enter image description here

If I press second time the button Open to open a file the File Name show the path of the previous selected file (see on image) How I can clear this path every time he press Open button?

enter image description here

score 11 · Accepted Answer · answered Jun 19 '12 at 08:32

You are probably using the same instance of an OpenFileDialog each time you click the button, which means the previous file name is still stored in the FileName property. You should clear the FileName property before you display the dialog again:

ofd.FileName = String.Empty;
if (ofd.ShowDialog() == DialogResult.OK)
     text = File.ReadAllText(ofd.FileName, Encoding.Default);

score 6 · Answer 2 · edited Jun 19 '12 at 09:36

6

try this:

ofd.FileName = String.Empty;

edited Jun 19 '12 at 09:36

John Woo

258,903
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answered Jun 19 '12 at 09:34

Clint Ceballos

151
3

score 3 · Answer 3 · answered Jun 19 '12 at 08:32

3

You need to reset the filename.

   openFileDialog1.FileName= "";

Or

   openFileDialog1.FileName= String.Empty()

answered Jun 19 '12 at 08:32

Gaz Winter

2,924
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score 3 · Answer 4 · answered Jun 19 '12 at 08:34

3

you can simply add this line before calling ShowDialog():

ofd.FileName = String.Empty;

answered Jun 19 '12 at 08:34

John Woo

258,903
69
498
492

score 1 · Answer 5 · answered Jun 19 '12 at 08:33

1

To clear just the filename (and not the selected path), you can set the property FileName to string.Empty.

answered Jun 19 '12 at 08:33

MatthiasG

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score 0 · Answer 6 · answered Jun 19 '12 at 08:43

private void button1_Click(object sender, EventArgs e)
    {
        openFileDialog1.ShowDialog();
    }

    private void openFileDialog1_FileOk(object sender, CancelEventArgs e)
    {
        label1.Text = sender.ToString();
    }

What about this one.

c# Openfiledialog

6 Answers6