PHP strstr difference issue

Question

So currently I have a problem. I have this snippet of code to see if a phrase is present in another phrase:

if(strstr($matches[1], $query))

So for example if:

$matches[1] = "arctic white"
$query = "arctic"

In the case above, the code would detect that the phrase "arctic" is in the phrase "arctic white" although, what I want is for it to detect if it is inside words as well and not just phrases.

For example if:

$matches[1] = "antarctica"
$query = "arctic"

In that case the script would NOT detect the word "arctic" in "antarctica" although it is. So I was wondering, how can I edit if(strstr($matches[1], $query)) so it would detect ALL words that have the $query content in it? Please help!

It already detects just fine. I am guessing you actually want to find the words which contain the $query contents? — oxygen, Jun 09 '12 at 19:15
Yep, I want to detect all words that contain the $query content. — S17514, Jun 09 '12 at 19:19
@Gokhan137: Ok, that's not what your question says at all. Please edit your question to explain exactly what you're looking for. — Oliver Charlesworth, Jun 09 '12 at 19:23

score 2 · Accepted Answer · answered Jun 09 '12 at 19:23

2

You can use preg_match() for much better result. The preg_match doesn't encompass regular expressions only. It can do exactly what you need. i.e.:

if (preg_match("/arctic/i", "antarctica")) {
    // it is there do something
} else {
    // it is not there do something else
}

btw, the small "i" means case sensitivity, check PHP manual for more examples: http://php.net/manual/en/function.preg-match.php

answered Jun 09 '12 at 19:23

Milan

3,209
1
35
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He corrected his post. He wants the words, you should show him how to collect matches. – oxygen Jun 09 '12 at 19:42
but he is showing just one array key -> value. Does he mean the key will hold a long text which needs to be searched ? Please clarify. – Milan Jun 16 '12 at 08:12

score 0 · Answer 2 · answered Jun 09 '12 at 19:18

0

use strpos()

example:

$word = "antarctica";
$find = "arctic";

$i = strpos($word, $find);

if($i === false)
{
echo "not found";
}

else
{
echo "found";
}

answered Jun 09 '12 at 19:18

PsychoMantis

993
2
13
29

PHP strstr difference issue

2 Answers2