Dynamic Binding in C#

Question

class A 
 {
   public virtual void WhoAreYou() { Console.WriteLine("I am an A"); }
 }
class B : A
{
  public override void WhoAreYou() { Console.WriteLine("I am a B"); }
}
class C : B
{
 public new virtual void WhoAreYou() { Console.WriteLine("I am a C"); }
}
class D : C 
{
  public override void WhoAreYou() { Console.WriteLine("I am a D"); }
}


C c = new D();
c.WhoAreYou();// "I am a D"
A a = new D();
a.WhoAreYou();// "I am a B" !!!!

How the reference is allocated internally,reference A contains the reference of B? Can any one explain Whats going On?

Um I might be wrong but I think this is what's happening. When you declare an object of class D and assign it to a class C --- class C has a virtual function and in that case it will just use D's overwrite function. But when you declare an object of class D and assign it to a class A what happens is because D inherits from C and C from B and B finally inherits from A but at the same time overwrites A then you have that print statement. — Florin Stingaciu, Jun 01 '12 at 15:56
how about: reading the msdn and trying to understand the virtual/override/new-machine? your example is totally clear! — , Jun 01 '12 at 15:59
@Flo: In first case the object C has the reference of D it calls D's method. But in Second case obviously A has the reference of D, while method invoke how it invoke B's method (what happen internally).. Quiet Confusing.. — C-va, Jun 01 '12 at 16:04
Does `new virtual` even make sense conceptually, what is your intended result? — Matthew, Jun 01 '12 at 16:27
@Matthew : Obviously hide the base class implementation and let the derived to override. — C-va, Jun 01 '12 at 17:39
@Matthew: But Compiler throw warning if i let the method with virtual alone. — C-va, Jun 02 '12 at 05:51
@Matthew: Ya right. But if i put override it will invoke D's method,Obviously the last one in override hierarchy. — C-va, Jun 02 '12 at 16:18
@Matthew : Ur right. But my point for this case : A a = new D(); a.WhoAreYou(); — C-va, Jun 02 '12 at 16:38

score 7 · Accepted Answer · answered Jun 01 '12 at 16:00

In class C, the method WhoAreYou() doesn't override the base class method, as it is defined with new keyword which adds a new method with the same name which hides the base class method. That is why this:

C c = new D();
c.WhoAreYou();// "I am a D"

invokes the overridden method in D which overrides its base class method defined with new keyword.

However, when the target type is A, then this:

A a = new D();
a.WhoAreYou();// "I am a B" !!!!

invokes the overridden method in B, as you're calling the method on a of type A whose method is overriden by B.

Thanks for the reply Nawaz. A has the reference of D, A doesnt know about its child classes. So, I have to track from derived one. Is it so? If not means .. But it will be better if how the reference of D call B's method and how it tracks the derived classes from A (in the aspect of method tables) like internal stuff.. — C-va, Jun 02 '12 at 06:10

score 3 · Answer 2 · answered Jun 01 '12 at 16:00

Your class C WhoAreYou() method is 'new', and therefor hiding the one from B. That means that the override in class D is overriding C's method instead of B's (which is overriding A's).

Since you have a reference to an A, the furthest down the hierarchy of it's WhoAreYou() function is the one in class B.

http://msdn.microsoft.com/en-us/library/435f1dw2.aspx

score 1 · Answer 3 · answered Jun 01 '12 at 18:24

1

It is mean, that the C's

public new virtual void WhoAreYou(){}

breaks the chain of virtual methods.

When you call the method WhoAreYou() of D by reference of A. The virtuality starts work, but it breaks at C.

answered Jun 01 '12 at 18:24

Hamlet Hakobyan

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Dynamic Binding in C#

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