How to call a function when shadowbox finished to open

Question

i need to call a function when shadowbox is opened and displayed in my page. I try this:

Shadowbox.open({
    content:    contentD,
    player:     "html",
    title:      "Pubblicazione annunci in corso...",
    height:     350,
    width:      350,
    options: { 
            modal:   true,
            onOpen: myOpen
    }
});

function myOpen(){
   alert('ok');
}

My problem is that alert('ok') is shown before shadowbox is displayed, what can i do? can someone help me?

unfortunately there're not other suitable hooks and the author didn't provided the original source in the package, so it's difficult to debug the code. - dannazione! :| — Fabrizio Calderan, May 24 '12 at 11:09
Have you tried to set timeout for alert like `setTimeout(function() { alert('ok'); }, 1);`? — VisioN, May 24 '12 at 11:09
@VisioN, it doesn't works.. alert message is shown before shadowbox is displayed.. — Jayyrus, May 24 '12 at 12:00
@F.Calderan, the source for Shadowbox v3.0.3 is on [gitHub](https://github.com/mjijackson/shadowbox/tree/v3.0.3). — arttronics, May 25 '12 at 11:52

score 1 · Accepted Answer · answered May 24 '12 at 12:17

1

Change onOpen by onClose ;)

Shadowbox.open({
    content:    contentD,
    player:     "html",
    title:      "Pubblicazione annunci in corso...",
    height:     350,
    width:      350,
    options: { 
            modal:   true,
            onClose: myOpen
    }
});

answered May 24 '12 at 12:17

SKJ

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i try onFinish and the result is what i need! thanks so much! :) – Jayyrus May 24 '12 at 12:24
Glad to help :) – SKJ Oct 16 '17 at 00:17

How to call a function when shadowbox finished to open

1 Answers1