Finding out whether a website returns 200

Question

I was using the following code to check whether a link that a user provides really points to an existing website:

$headers=get_headers($imageurl);
if (strpos($headers[0], '200') === false) {
    echo "not valid1";
    exit;
}

As test, I use the img http://cdn.thegloss.com/files/2012/04/stormtr.jpg

As long as I use this on my localhost, it works fine - i.e. it said that the url is valid and did not echo "not valid1" - now it is on a different server and it echoes "not valid1". How come? Anybody any idea?

Thanks! Dennis

This is working ok for me. What does it look like if you `var_dump($headers)`? — Travesty3, May 18 '12 at 16:51
According to [the manual](http://php.net/manual/en/function.get-headers.php), `get_headers` "Returns an indexed or associative array with the headers, or FALSE on failure." So it sounds like it failed somehow. Perhaps a firewall issue? — Travesty3, May 18 '12 at 16:55
Is your server allowed to access the internet? Is it behind a proxy? — Ahatius, May 18 '12 at 16:55

score 2 · Accepted Answer · answered May 18 '12 at 16:55

2

get_headers() returns false because it failed.
It might be because allow_url_fopen is set to Off on the server.

answered May 18 '12 at 16:55

Samy Dindane

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+1. I was thinking the same thing, but the documentation isn't exactly clear. – Jeff Lambert May 18 '12 at 16:59

score 1 · Answer 2 · answered May 18 '12 at 16:59

1

Try this it will return only the 3-digit HTTP response code

function get_response_code($theURL) {
    $headers = get_headers($theURL);
    return substr($headers[0], 9, 3);
}

answered May 18 '12 at 16:59

Moyed Ansari

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It was because allow_url_fopen was disabled. THanks! – Dennis Hackethal May 18 '12 at 17:01

Finding out whether a website returns 200

2 Answers2