Is there any way to extend an application into another application for mdi ? For ex. I have 3 applications : "Transaction" ,"SalesOrder" & "PurchaseOrder" i want to reuse "Transaction" by extending it in "SalesOrder" & "PurchaseOrder" . Whats the clean way to do it?
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2 Answers
1
Simply you can define an application
with specific name and then extend
from that.
BaseApp.js
:
Ext.application({
name: 'BaseApp',
launch: function () {
alert("Base App Launch");
}
});
ChildApp.js
:
Ext.application({
//extend from base app
extend: 'BaseApp',
name: 'ChildApp',
launch: function () {
alert("Child App Launch");
}
});

Afshin Mehrabani
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0
Yes it's possible since ExtJS 4.2.
Check documentation section 'Deriving from Ext.app.Application' at http://docs.sencha.com/extjs/4.2.2/#!/api/Ext.app.Application
Here is a small example:
Ext.define('Transaction.Application', {
extend: 'Ext.app.Application',
requires: [],
// application namespace
name: 'Transaction',
// name of the app instance in DOM (e.g. Transaction.instance)
//appProperty: 'instance',
// application folder
appFolder: '/js/Transaction',
autoCreateViewport: true,
controllers: [
],
views: [
],
launch: function() {
console.log('application started');
}
});
Ext.define('SalesOrder.Application', {
extend: 'Transaction.Application',
requires: [],
// application namespace
name: 'SalesOrder',
// application folder
appFolder: '/js/SalesOrder',
autoCreateViewport: false,
controllers: [
],
views: [
],
launch: function() {
Ext.create('Ext.container.Viewport');
this.callParent();
}
});
Ext.define('PurchaseOrder.Application', {
extend: 'Transaction.Application',
requires: [],
// application namespace
name: 'PurchaseOrder',
// application folder
appFolder: '/js/PurchaseOrder',
autoCreateViewport: false,
controllers: [
],
views: [
],
launch: function() {
Ext.create('Ext.container.Viewport');
this.callParent();
}
});
Ext.application('PurchaseOrder.Application');
// Then you can acces your application instance anywhere:
var app = PurchaseOrder.getApplication();

Viacheslav Dobromyslov
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