Shell script showing errors while executing in Linux

Question

SCRIPT :

IMAGE=$imgvalue;
if  [ $imgvalue :=1 ]
then
    echo DO=ABC;
elif [ $imgvalue :=2 ]
then
    echo DO=ETC;
elif [ $imgvalue :=3 ]
then
    echo DO=XYZ;
else
    echo "$imgvalue is unsupported";
    exit 1; 
fi

In the script above, IMAGE=1, IMAGE=2, IMAGE=3 whatever may be the value I have assigned. It's showing only DO=ABC. Other conditions not working. Can anyone explain what's wrong with my script?

Very similar to your last [question](http://stackoverflow.com/q/10509775/1330481) ? — UNECS, May 09 '12 at 06:31
Or is it because of exporting to the new shell not the command line shell? — UNECS, May 09 '12 at 06:40

score 0 · Answer 1 · answered Nov 06 '12 at 20:10

If $imgvalue is not an empty string, your first test is a syntax error, so I am assuming it is empty in the tests you are doing. In that case, your first test is equivalent to:

if [ :=1 ]

which is always true because :=1 is not an empty string. You probably meant to write:

if [ "$imgvalue" = 1 ]

Shell script showing errors while executing in Linux

1 Answers1