I'm asked a question, when I traverse my binary tree, is it possible to get the node above the current node ? As a double linked list.
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If you build it as a double-linked, then yes, go to the "parent" property. abstract example:
struct node {
struct node *parent; // << this is the parent, just access it
struct node *rchild;
struct node *lchild;
int val;
}
Else, you will need to cache the previous node at each access to a child node.
Note that a doubly link list is not the same as binary tree (in list each item has one child).

Vadim Kotov
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