MultiUserChat get chat room user?

Question

I am working on ASmack. Is it workable to get chat room user list using asmack? http://www.igniterealtime.org/builds/smack/docs/latest/documentation/extensions/muc.html This list have not shown. Please give me some idea.

score 2 · Accepted Answer · answered May 05 '12 at 10:26

2

Which list?

You can only call getOccupants() if you are an occupant of the MUC or, in other words, if have joined the MUC.

answered May 05 '12 at 10:26

Flow

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I am calling getOccupants() but it's not returning occupants list all time. according to my problem i asked one Question in SO look at this http://stackoverflow.com/questions/16335872/how-to-get-list-of-occupants-from-room-in-multiuserchat , and tell me how to solve this. – RajaReddy PolamReddy May 02 '13 at 10:46

score 1 · Answer 2 · answered Jan 22 '14 at 18:18

1

getOccupants() doesnt work for me. So you can try the code below:

 try {         
       ServiceDiscoveryManager discoManager =  ServiceDiscoveryManager.getInstanceFor(xmppConn);
       DiscoverItems discoItems = discoManager.discoverItems(roomJID);
       Iterator<DiscoverItems.Item> occupants = discoItems.getItems();  

     } catch (XMPPException e) {
       e.printStackTrace();                
     }

answered Jan 22 '14 at 18:18

rmldts

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I am using 4.1.0 rc1 and i am not able to get occupants by getOccupants(). ServiceDiscoveryManager works for me. – Hitendra Apr 02 '15 at 08:21

score 0 · Answer 3 · answered Apr 11 '15 at 13:09

i was able to get the List Of user's available in the Chat Room Of XMPP by the Simple Following Method passing the Parameter as MultiUserChat Object.

public static List<String> findMulitUser(MultiUserChat muc) {
    List<String> listUser = new ArrayList<String>();
    Iterator<String> it = muc.getOccupants();
    // Traverse the chat room name
    while (it.hasNext()) {
        // Chat room members name
        String name = StringUtils.parseResource(it.next());
        System.out.println("Name Of Occupants------>" + name);
        listUser.add(name);
    }
    return listUser;
}

MultiUserChat get chat room user?

3 Answers3