I know c# has Array.FindAll
and Array.IndexOf
.
Is there a Array.FindAllIndexOf
which returns int[]
?
I know c# has Array.FindAll
and Array.IndexOf
.
Is there a Array.FindAllIndexOf
which returns int[]
?
string[] myarr = new string[] {"s", "f", "s"};
int[] v = myarr.Select((b,i) => b == "s" ? i : -1).Where(i => i != -1).ToArray();
This will return 0, 2
If the value does not exist in the array then it will return a int[0].
make an extension method of it
public static class EM
{
public static int[] FindAllIndexof<T>(this IEnumerable<T> values, T val)
{
return values.Select((b,i) => object.Equals(b, val) ? i : -1).Where(i => i != -1).ToArray();
}
}
and call it like
string[] myarr = new string[] {"s", "f", "s"};
int[] v = myarr.FindAllIndexof("s");
You can write something like :
string[] someItems = { "cat", "dog", "purple elephant", "unicorn" };
var selectedItems = someItems.Select((item, index) => new{
ItemName = item,
Position = index});
or
var Items = someItems.Select((item, index) => new{
ItemName = item,
Position = index}).Where(i => i.ItemName == "purple elephant");
Searches for an element that matches the conditions defined by the specified predicate, and returns all the zero-based index of the occurrence within the entire System.Array.
public static int[] FindAllIndex<T>(this T[] array, Predicate<T> match)
{
return array.Select((value, index) => match(value) ? index : -1)
.Where(index => index != -1).ToArray();
}
I know this is an old post, but you can try the following,
string[] cars = {"Volvo", "BMW", "Volvo", "Mazda","BMW","BMW"};
var res = Enumerable.Range(0, cars.Length).Where(i => cars[i] == "BMW").ToList();
returns {1,4,5} as a list
No, there is not. But you can write your own extension method.
public static int[] FindAllIndexOf<T>(this T[] a, Predicate<T> match)
{
T[] subArray = Array.FindAll<T>(a, match);
return (from T item in subArray select Array.IndexOf(a, item)).ToArray();
}
and then, for your array, call it.
I've used Nikhil Agrawal's answer to create the following related method, which may be useful.
public static List<int> FindAllIndexOf<T>(List<T> values, List<T> matches)
{
// Initialize list
List<int> index = new List<int>();
// For each value in matches get the index and add to the list with indexes
foreach (var match in matches)
{
// Find matches
index.AddRange(values.Select((b, i) => Equals(b, match) ? i : -1).Where(i => i != -1).ToList());
}
return index;
}
Which takes a list with values and a list with values that are to be matched. It returns a list of integers with the index of the matches.
You can solve this problem by creating only 2 integer variables. More power to you!
string[] seasons= { "Fall","Spring", "Summer", "Fall", "Fall", "Winter"};
int i = 0;
int IndexOfFallInArray = 0;
int[] IndexesOfFall= new int[seasons.Length];
foreach (var item in seasons)
{
if (item == "Fall")
{
IndexesOfFall[i] = IndexOfFallInArray;
i++;
}
IndexOfFallInArray++;
}
How about simply:
public static IEnumerable<int> Available()
{
for (int i = 0; i < myarr.Length; i++)
{
if (myarr[i] is null) //Your predicate here...
yield return i;
}
}
I'm aware that the question is answered already, this is just another way of doing it. note that I used ArrayList
instead of int[]
// required using directives
using System;
using System.Collections;
String inputString = "The lazy fox couldn't jump, poor fox!";
ArrayList locations = new ArrayList(); // array for found indexes
string[] lineArray = inputString.Split(' '); // inputString to array of strings separated by spaces
int tempInt = 0;
foreach (string element in lineArray)
{
if (element == "fox")
{
locations.Add(tempInt); // tempInt will be the index of current found index and added to Arraylist for further processing
}
tempInt++;
}