How do you show a 404 when there are extra URL segments in CodeIgniter?

Question

Basically, I have a CodeIgniter site that registers users through this url:
http://website.com/user/register/1

Unfortunately, when you pass extra arguments in the URL like this: http://website.com/user/register/1/extraargs/extraargs

Here is my code:

<?php
class User extends CI_Controller
{
    public function register($step = NULL)
    {
        if (($step!=NULL)&&($step == 1 || $step == 2 || $step == 3)) {
            if ($step == 1){
                $this->load->view('registration_step1');
            }
        } else {
            show_404();
        }
    }
}
?>

It doesn't show a 404. It simply ignores the extra arguments. I want it so that the extra arguments wouldn't affect the URL. I want to show a 404 if there are extra URL arguments. How do you do this? Also, can the extra URL segments affect security? Thanks.

It won't affect security since there will be extra values passed which your system simply won't use. — Robin Castlin, May 01 '12 at 10:24

score 5 · Accepted Answer · answered May 01 '12 at 10:22

5

Not sure why you'd want to do that really, but you could use func_num_args() and validate from that, i.e.,

public function register($step = NULL)
{
  if ( func_num_args() > 1 ) show_404();
}

answered May 01 '12 at 10:22

Nick Pyett

3,338
1
23
27

How do you show a 404 when there are extra URL segments in CodeIgniter?

1 Answers1