debug and production versions of javascript

Question

I have a js file that contains lots of debug statements. I am looking for a script or compiler that will skip these debug statements, and can provide a production version.

function init(){
  console.log('initing the lib');
  ...
  .. some code here ..
  ...
  console.log('init over');
}

I need to have a production version that has none of these console.log's. This will allow for writing a debug version that can be used to see where exactly the error is occuring.

what are "debug statements" exactly? can you explain with a few sample code? — Joseph, Apr 30 '12 at 08:01
can't your IDE do a regexp replace of `/console\.log\(.*\)/`? — Joseph, Apr 30 '12 at 08:27
this will be manual. We need something that we can use for CI testing. — Amit, Apr 30 '12 at 08:28
who said anything about manual, when [there exists automation](http://stackoverflow.com/q/6595429/575527) - this might be on Mac, but surely there are similar tools in other platforms. — Joseph, Apr 30 '12 at 08:32

KooiInc · Accepted Answer · 2012-04-30T08:51:35.540

1

Maybe googles closure compile can help you out?

If you're worried about the console.log (seems that's what you mean by 'debug statements'), it may be an idea to override it in production:

var isProduction = true; //or false
if (isProduction){
 window.console = {log: function(){return true;}};
}

edited Apr 30 '12 at 08:51

answered Apr 30 '12 at 08:06

KooiInc

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Does it have something that lets you mark a section as debug code it should omit? – T.J. Crowder Apr 30 '12 at 08:20
In the faq (http://code.google.com/p/closure-compiler/wiki/FAQ), this is stated: *Closure Compiler will remove code that isn't used or exported.* Maybe this is applicable: https://developers.google.com/closure/compiler/docs/api-tutorial3?#removal – KooiInc Apr 30 '12 at 08:29
You will maybe want to mark this variable as constant: `/** @const */ var DEBUG = false;` – Niko May 01 '12 at 07:56

debug and production versions of javascript

1 Answers1